1065 A+B and C (64bit)

Given three integers A, B and C in [−2^63^,2^63^], you are supposed to tell whether A+B>C.

Input Specification:

The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line Case #X: true if A+B>C, or Case #X: false otherwise, where X is the case number (starting from 1).

Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Sample Output:

1
2
3

Case #1: false
Case #2: true
Case #3: false

浅析

送分题

Code

#include 
using namespace std;
int main() {
    int n;
    scanf("%d", &n);
    for(int i = 0; i < n; i++) {
        long long a, b, c;
        scanf("%lld %lld %lld", &a, &b, &c);
        long long sum = a + b;
        if(a > 0 && b > 0 && sum < 0) {
            printf("Case #%d: true\n", i + 1);
        } else if(a < 0 && b < 0 && sum >= 0){
            printf("Case #%d: false\n", i + 1);
        } else if(sum > c) {
            printf("Case #%d: true\n", i + 1);
        } else {
            printf("Case #%d: false\n", i + 1);
        }
    }
    return 0;
}