1060 Are They Equal

If a machine can save only 3 significant digits, the float numbers 12300 and 12358.9 are considered equal since they are both saved as 0.123×105 with simple chopping. Now given the number of significant digits on a machine and two float numbers, you are supposed to tell if they are treated equal in that machine.

Input Specification:

Each input file contains one test case which gives three numbers N, A and B, where N (<100) is the number of significant digits, and A and B are the two float numbers to be compared. Each float number is non-negative, no greater than 10^100^, and that its total digit number is less than 100.

Output Specification:
For each test case, print in a line YES if the two numbers are treated equal, and then the number in the standard form 0.d[1]...d[N]*10^k (d[1]>0 unless the number is 0); or NO if they are not treated equal, and then the two numbers in their standard form. All the terms must be separated by a space, with no extra space at the end of a line.

Note: Simple chopping is assumed without rounding

Sample Input:
1
3 12300 12358.9

Sample Output:
1
YES 0.123*10^5

Sample Input 2:
1
3 120 128

Sample Output 2:
1
NO 0.120*10^3 0.128*10^3

Code
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#include
#include
using namespace std;
int n;
string deal(string s,int& e){
int i = 0;
while(s.length()>0&&s[0]=='0')
s.erase(s.begin());
if(s[0]=='.'){
s.erase(s.begin());
while(s.length()>0&&s[0]=='0'){
s.erase(s.begin());
e--;
}
}else{
while(i'.'){
e++;
i++;
}
if(s[i]=='.')
s.erase(s.begin() + i);
}
if(s.length()==0) e=0;
string res;

for (int j = 0; j < n;j++){
if(j
res += s[j];
else
res += '0';
}
return res;
}

int main(){
string s1, s2, s3, s4;
int e1 = 0, e2 = 0;
cin >> n >> s1 >> s2;
s3 = deal(s1, e1);
s4 = deal(s2, e2);
if(s3==s4&&e1==e2)
cout << "YES 0." << s3 << "*10^" << e1<<endl;
else
cout << "NO 0." << s3 << "*10^" << e1 << " 0." << s4 << "*10^" << e2<<endl;
return 0;
}